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Java Example - Finding a Specified Element in an Array

Java Examples

The following example demonstrates how to use the contains() method to find a specified element in an array:

Main.java File

import java.util.ArrayList;

public class Main {
    public static void main(String[] args)  {
        ArrayList<String> objArray = new ArrayList<String>();
        ArrayList<String> objArray2 = new ArrayList<String>();
        objArray2.add(0,"common1");
        objArray2.add(1,"common2");
        objArray2.add(2,"notcommon");
        objArray2.add(3,"notcommon1");
        objArray.add(0,"common1");
        objArray.add(1,"common2");
        System.out.println("objArray elements: " + objArray);
        System.out.println("objArray2 elements: " + objArray2);
        System.out.println("Does objArray contain the string 'common2'? : "
        + objArray.contains("common2"));
        System.out.println("Does objArray2 contain the array objArray? : "
        + objArray2.contains(objArray));
    }
}

The output of the above code is:

objArray elements: [common1, common2]
objArray2 elements: [common1, common2, notcommon, notcommon1]
Does objArray contain the string 'common2'? : true
Does objArray2 contain the array objArray? : false

Java Examples

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