❮ C Function Ldexp C Function Isdigit ❯

C Library Function - `ispunct()`

C Standard Library - <ctype.h>

Description

The C library function int ispunct(int c) checks whether the passed character is a punctuation character. A punctuation character is any graphical character (as in isgraph) that is not alphanumeric (as in isalnum).

Declaration

Here is the declaration for the ispunct() function.

int ispunct(int c);

Parameters

c -- This is the character to be checked.

Return Value

This function returns a non-zero value (true) if c is a punctuation character, otherwise it returns 0 (false).

Example

The following example demonstrates the use of the ispunct() function.

#include <stdio.h>
#include <ctype.h>

int main()
{
   int var1 = 't';
   int var2 = '1';
   int var3 = '/';
   int var4 = ' ';

   if( ispunct(var1) )
   {
       printf("var1 = |%c| is a punctuation character\n", var1 );
   }
   else
   {
       printf("var1 = |%c| is not a punctuation character\n", var1 );
   }
   if( ispunct(var2) )
   {
       printf("var2 = |%c| is a punctuation character\n", var2 );
   }
   else
   {
       printf("var2 = |%c| is not a punctuation character\n", var2 );
   }
   if( ispunct(var3) )
   {
       printf("var3 = |%c| is a punctuation character\n", var3 );
   }
   else
   {
       printf("var3 = |%c| is not a punctuation character\n", var3 );
   }
   if( ispunct(var4) )
   {
       printf("var4 = |%c| is a punctuation character\n", var4 );
   }
   else
   {
       printf("var4 = |%c| is not a punctuation character\n", var4 );
   }

   return(0);
}

Let's compile and run the above program, which will produce the following result:

var1 = |t| is not a punctuation character
var2 = |1| is not a punctuation character
var3 = |/| is a punctuation character
var4 = | | is not a punctuation character