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C Language Example - Counting Various Characters in a String

C Language Examples

Count vowels, consonants, digits, and whitespace characters in a string.

Example

#include <stdio.h>

int main()
{
    char line[150];
    int i, vowels, consonants, digits, spaces;

    vowels = consonants = digits = spaces = 0;

    printf("Enter a string: ");
    scanf("%[^\n]", line);

    for(i=0; line[i]!='\0'; ++i)
    {
        if(line[i]=='a' || line[i]=='e' || line[i]=='i' ||
           line[i]=='o' || line[i]=='u' || line[i]=='A' ||
           line[i]=='E' || line[i]=='I' || line[i]=='O' ||
           line[i]=='U')
        {
            ++vowels;
        }
        else if((line[i]>='a'&& line[i]<='z') || (line[i]>='A'&& line[i]<='Z'))
        {
            ++consonants;
        }
        else if(line[i]>='0' && line[i]<='9')
        {
            ++digits;
        }
        else if (line[i]==' ')
        {
            ++spaces;
        }
    }

    printf("Vowels: %d", vowels);
    printf("\nConsonants: %d", consonants);
    printf("\nDigits: %d", digits);
    printf("\nWhitespace characters: %d", spaces);

    return 0;
}

Output:

Enter a string: tutorialpro123 erkcomsww dftutorialpro
Vowels: 8
Consonants: 15
Digits: 3
Whitespace characters: 2

C Language Examples

❮ C Examples Printf Float C Exercise Example91 ❯