Returning Arrays from Functions in C++
C++ does not allow returning an entire array as a function argument. However, you can return a pointer to an array by specifying the array's name without an index.
If you want to return a one-dimensional array from a function, you must declare a function returning a pointer, like this:
int * myFunction()
{
// Function body
}
Additionally, C++ does not support returning the address of a local variable outside the function unless the local variable is defined as a static variable.
Now, let's look at the following function, which generates 10 random numbers and returns them using an array:
Example
#include <iostream>
#include <cstdlib>
#include <ctime>
using namespace std;
// Function to generate and return random numbers
int * getRandom()
{
static int r[10];
// Set seed
srand((unsigned)time(NULL));
for (int i = 0; i < 10; ++i)
{
r[i] = rand();
cout << r[i] << endl;
}
return r;
}
// Main function to call the above defined function
int main()
{
// A pointer to an integer
int *p;
p = getRandom();
for (int i = 0; i < 10; i++)
{
cout << "*(p + " << i << ") : ";
cout << *(p + i) << endl;
}
return 0;
}
When the above code is compiled and executed, it produces the following result:
624723190
1468735695
807113585
976495677
613357504
1377296355
1530315259
1778906708
1820354158
667126415
*(p + 0) : 624723190
*(p + 1) : 1468735695
*(p + 2) : 807113585
*(p + 3) : 976495677
*(p + 4) : 613357504
*(p + 5) : 1377296355
*(p + 6) : 1530315259
*(p + 7) : 1778906708
*(p + 8) : 1820354158
*(p + 9) : 667126415